August 27, 2025
The valid parentheses problem is an easy problem to solve. The algorithm is:
stack = []
for every char in str
if char is an opening parenthesis
stack.push (char)
if char is a closing parenthesis ...
stack = []
for every char in str
if char is an opening parenthesis
stack.push (char)
if char is a closing parenthesis ...
algorithms, bit manipulation, exercise, go, memory, optimization, performance